Phase Space Factor: Confused About 3D to 4D Conversion

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SUMMARY

The discussion focuses on the conversion between three-dimensional and four-dimensional phase space in the context of particle physics, specifically referencing the equation d3p / 2E = θ(E) δ(p2 - m2) d4p. The participants clarify that this equation does not represent a strict equality but rather indicates that both sides correspond to the same integral measures under the assumption of positive energy and on-shell conditions (p^2 = m^2). The delta function is identified as a critical component that reduces the dimensionality of the integral.

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Josh1079
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Hi,

I'm recently reading "Particle Physics in the LHC Era" and there is a part about the phase space factor that confuses me. When giving the Lorentz invariant phase space, they wrote:

d3p / 2E = θ(E) δ(p2 - m2) d4p

This is very confusing as it equates a three dimensional differential to a four dimensional one. Is there anything I didn't take into account?

Thank you!
 
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Well...actually that equal sign is not really an equal sign. It just means these two are the same integral measures and that's because we're assuming the energy is positive and the particle is on-shell(i.e. satisfies ## p^2=m^2 ##).
So it actually means ## \displaystyle \int f(E,\mathbf p) \frac{d^3\mathbf p}{2E}=\int f(p) \theta(E)\delta(p^2-m^2)d^4p ##, where ##\mathbf p## is a three-vector and ##p## is a four-vector.
 
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Josh1079 said:
Is there anything I didn't take into account?

The delta function, which functions as a constraint that reduces the dimensionality by 1.
 
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Thank you so much ShayanJ! I get it now!

And also thanks to Vanadium 50 for pointing that out!
 

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