Photoelectric absorption and low energy electron absorption

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Discussion Overview

The discussion revolves around the photoelectric absorption effect in gamma ray spectroscopy, particularly focusing on the liberation of electrons during this process and the implications for energy transfer and characteristic radiation. Participants explore the relationship between photoelectric absorption and the Auger effect, as well as the potential for light photon generation in scintillation detectors.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant expresses confusion regarding the liberation of additional electrons alongside the photoelectron during photoelectric absorption, questioning their origin and the resulting characteristic radiation.
  • Another participant suggests that the scenario described may relate to the Auger effect, where an inner shell electron's vacancy leads to energy release, potentially resulting in the emission of another electron or radiation.
  • A follow-up inquiry considers whether Auger electrons, resulting from collisions in an ideal scintillation detector, could generate light photons, linking the energy of gamma photons to the output pulse energy in spectroscopy.
  • Participants reference external documents for further reading, indicating a desire for additional context or clarification on the topic.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the specifics of the electrons involved in photoelectric absorption or the implications for light photon generation. Multiple viewpoints and interpretations of the phenomena remain present.

Contextual Notes

The discussion includes assumptions about the behavior of electrons during photoelectric absorption and the Auger effect, as well as the conditions under which scintillation detectors operate. There are unresolved questions regarding the energy dynamics and the characteristics of emitted radiation.

Taylor_1989
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I have am currently reading Radiation Detection and Measurement, by Gleen F.Knoll, and in chapter 10 page 309.

And have come across something that is causing a bit of confusion, for context the chapter is on gamma ray spectroscopy.

So in the text it say's 'Thus the effect of photoelectric absorption is the liberation of photo electron, which carries off most of the energy gamma ray energy, together with one or more low energy electron corresponding to absorption of the original binding energy of the photo electron'.

In most thing I have every covered on photoelectric it have never talked about the addition of other electrons leaving the atom with the photo electron.

What electron are leaving the atom with the photo electron, which shell do they come from and surely they must be causing some characteristic radiation to take place?
 
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I don't have the book but this sounds like a description of the Auger effect. If the high energy electron comes from an inner shell another electron jumps down into the now empty energy level, this release energy - sometimes as radiation, sometimes as another electron that gets kicked out.
 
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mfb said:
I don't have the book but this sounds like a description of the Auger effect. If the high energy electron comes from an inner shell another electron jumps down into the now empty energy level, this release energy - sometimes as radiation, sometimes as another electron that gets kicked out.

Ah okay, so for gamma spectroscopy then, imagining and ideal scintillation detector where nothing escapes the detector then if a gamma photo hits and absorption atom and through photoelectric absorption then majority of the energy goes to photo electrons which then imparts that energy through collisions and the auger electrons give off there energy during the collision. Dose this mean that the auger electron have enough energy to cause a light photon? As in spectroscopy the energy of the gamma photon is proportional to the energy of the pulse being output?
 

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