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Photoelectric Effect IV Curves

  1. Mar 16, 2013 #1
    1. The problem statement, all variables and given/known data
    In photoelectric effect, why the saturated current starts at the y axis (0,y)? and what is the reason for that gradient at the negative x axis (Shown as a red line)?

    2. Relevant equations
    -


    3. The attempt at a solution
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    Attached Files:

  2. jcsd
  3. Mar 16, 2013 #2

    epenguin

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    This part was missing
     
  4. Mar 16, 2013 #3
    2. Relevant equations
    hf = 1/2 mv^2 + e(Vs)

    3. The attempt at a solution
    Because the rate of emitting electrons is increasing from zero to that value.

    Am I right?
     
  5. Mar 16, 2013 #4

    epenguin

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    Well, it's more the rate of collecting electrons I'd say, but that's only a description of what's observed and what the graph says, not an explanation of why it's like that.
     
    Last edited: Mar 16, 2013
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