Photoelectric efffect question

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SUMMARY

The relationship between maximum electric current and light intensity in photoelectric effect scenarios is defined by quantum efficiency (QE). In photomultiplier tubes (PMTs), a theoretical maximum QE of 1 indicates that 6.25 x 1018 photons per second can produce 1 amp of photoelectrons. Actual PMTs have demonstrated a QE exceeding 50% at a wavelength of 4000 Angstroms, showcasing their efficiency in converting light into electric current.

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NMphoton
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Hey there,
I know this may seem like a stupid question but what is the relationship between the maximum electric current and the intensity of light?

:)
 
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If you have a thin surface emitting photoelectrons (semitransparent film on the back side of a clear glass window), and a large electric field perpendicular to the surface, like in photomultipliers PMTs), the theoretical maximum quantum efficiency (QE) is 1. In this case, 6.25 x 10^18 photons per sec produces 1 amp of photoelectrons. In actual cases, PMTs have exceeded a QE of 50% at 4000 Angstroms.
 

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