What Is the Speed of the Slowest Electron That Can Excite a Hydrogen Atom?

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SUMMARY

The slowest electron capable of exciting a hydrogen atom must possess a speed of 1.9 x 106 m/s. This conclusion is derived from the first excitation energy of the hydrogen atom, which is 10.2 eV, and the electron charge-mass ratio of 1.7 x 1011 kg-1. The calculations utilize the equations relating energy (eV), kinetic energy (1/2 mv2), and photon energy (hf).

PREREQUISITES
  • Understanding of electron charge-mass ratio (e/m)
  • Familiarity with excitation energy concepts
  • Knowledge of kinetic energy equations
  • Basic principles of photon energy (hf)
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Homework Statement



The 1st excitation energy of hydrogen atom is 10.2 eV
electron charge- mass ratio (e/m) = 1.7 x 10 11 kg -1

Find speed of the slowest electron that can excite a hydrogen atom

Homework Equations



eV= 1/2 mv2 = hf = hc/lamda

hf = work function energy + 1/2 mv 2

The Attempt at a Solution



Ans : 1.9 x 106ms-1
 
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