- #1
SnoliF
- 5
- 0
A meson can be produced by a high energy photon scattering off a nucleon in an interaction such as
$$\gamma + p \rightarrow p + \pi^0$$
As long as the photon is sufficiently energetic, mesons heavier than the pion can be produced, as well as multiple mesons such as ##\pi^{+} + \pi^{-}## provided the net charge of the mesons is zero.
In reading about photoproduction, I've also see this interaction mentioned
$$\gamma + p \rightarrow n + \pi^+$$
but I have a question that I haven't been able to find an answer for- In the second interaction what process allows a proton to be converted to a neutron?
$$\gamma + p \rightarrow p + \pi^0$$
As long as the photon is sufficiently energetic, mesons heavier than the pion can be produced, as well as multiple mesons such as ##\pi^{+} + \pi^{-}## provided the net charge of the mesons is zero.
In reading about photoproduction, I've also see this interaction mentioned
$$\gamma + p \rightarrow n + \pi^+$$
but I have a question that I haven't been able to find an answer for- In the second interaction what process allows a proton to be converted to a neutron?