# Phsyics Kinematics: cannonball shot straight up

1. Feb 28, 2010

### okgo

2. Feb 28, 2010

### jfy4

here is my math for it.

$$v_{y}=v\sin\theta$$
$$v_{x}=v\cos\theta$$

$$t=\frac{v\sin\theta}{g}$$
to get the total time in the air multiply by two, becuase that time is only half way.
$$x=v\cos\left(\theta\right) t$$
plug in t
$$x=\frac{2v^2\sin\theta \cos\theta}{g}$$

that should get you the distance traveled... i think but look over my math.

3. Mar 1, 2010

### okgo

Oh. I'm having trouble with the angle though. Not sure what it would be.

4. Mar 1, 2010

### okgo

and isn't there acceleartion in the x direction too?

5. Mar 1, 2010

### jfy4

From what i saw in the problem there were not any more forces than just gravity... and gravity only works in the y direction. your angle is the one given in the problem, 45.

6. Mar 1, 2010

### okgo

Oh I was talking about question 23. Hehe I already solved for question 22. Oh well. My exam is in 20 min. Dumdumdum. So it's okay. Thanks for the help though