Calculating the Density and Buoyant Force of a Pear in Water with Added Salt

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To calculate the density of the pear, it is established that it must be between 1 g/cm³ and 1.06 g/cm³, as the pear begins to float when the density of the saltwater solution reaches 1.06 g/cm³. The buoyant force acting on the pear is calculated to be 1.225 N. The apparent weight of the pear at the bottom of the beaker can be determined using the formula for apparent weight, which considers the true weight and buoyant force. The discussion emphasizes that the volume of the pear is not necessary for solving the posed questions. Overall, the calculations hinge on understanding the relationship between density, buoyant force, and apparent weight in the context of the pear's immersion in saltwater.
Kikien

Homework Statement


A 125g pear is immersed at the bottoming of a beaker of water which is filled with 500cm3 of water. Salt of mass 30g was then completely dissolved in the water before the pear begins to float (assume no change In Volume of the water ) given the density of pure water is 1 g /cm2
1. What is the density of the pear
2.claculate the buoyant force Acting on the pear before Saltwas added
3. Initially , what was the apparent weight of the pear in the bottom of the beaker?
4.how mush of the pear would float above the water if 100g of salt was dissolved in the water instead?

Homework Equations


Density=mass/volume
Buoyant force pvg
Apparent weight = true weight - buoyant force

The Attempt at a Solution


I can't find the volume of the pear [/B]
 
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You need to make some attempt at a solution. Note that you are not being asked for the volume of the pear; so one place to start would be to explain why you think you need to calculate the volume of the pear to get the answer being asked for.
 
Don't really get it
I just figured out that the density of the pear will be between 1 to 1.06 as the 1.06 is the density of water plus salt
The buoyant force is 1.225N
So the volume of the pear has to divide by the density of pure water or density of water with salt?
 
Last edited by a moderator:
Kikien said:
I just figured out that the density of the pear will be between 1 to 1.06 as the 1.06 is the density of water plus salt

Will it be "between" those two densities? The problem statement says that the pear is just starting to float when the density of water plus salt is 1.06 (500g of water + 30g of salt in 500 cm^3). What does that tell you?

Kikien said:
So the volume of the pear has to divide by the density of pure water or density of water with salt?

You don't need to know the volume of the pear to answer any of the questions.
 
Kikien said:
Buoyant force pvg

This isn't very clear. What do the symbols mean?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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