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Physical Chemistry Problem, Evacuated tube - where does reaction take place?

  1. Oct 14, 2012 #1
    1. The problem statement, all variables and given/known data
    Two balls, one soaked in concentrated HCl and the other in NH4OH are placed at the left and right ends of a 1m long evacuated glass tube, respectively. HCl and ammonia vaporize and travel down the tube, reacting to form a white ring where they meet. Where does the ring form?


    2. Relevant equations



    3. The attempt at a solution
    I'm not sure what to do with this. At first I thought it dealt with diffusion but I couldn't get anything useful (unless I'm overlooking something). Then I realised the tube is empty, so can I just use the average speed o the gas molecules and see where the gasses meet or will that not work? Speed is not a vector though, so do I have to find the velocity of the net movement of the gases towards each other? If so how would I calculate that?
    Thanks
     
  2. jcsd
  3. Oct 14, 2012 #2

    mfb

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    Staff: Mentor

    The speed of the molecules is somewhere at ~500m/s, which means that they need ~2ms to travel through the pipe in vacuum. The preparation of your experiment will need much more time.
    One of the gases might evaporate quicker (and therefore in a larger amount), and shift the reaction area towards the other side. That is just a guess, however.
     
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