Physical Chemistry- Using the integrated Vant Hoff Equation with K values.

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SUMMARY

The discussion centers on calculating the enthalpy of dissolution using the integrated Van't Hoff equation with equilibrium constants (K) for oxygen solubility in water at two temperatures: 15°C and 25°C. The equilibrium concentrations are 630 μmol/L and 517 μmol/L, respectively. A key insight is that the partial pressure of oxygen does not change during dissolution, allowing the simplification of the equilibrium constant expression to K = [O2]. This clarification resolves confusion regarding the necessity of including partial pressure in the calculation of K.

PREREQUISITES
  • Understanding of the Van't Hoff equation
  • Knowledge of equilibrium constants and their expressions
  • Familiarity with the concept of partial pressure in gas solubility
  • Basic principles of physical chemistry related to gas-liquid equilibria
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  • Study the derivation and applications of the Van't Hoff equation
  • Research the relationship between solubility and temperature changes in physical chemistry
  • Explore the concept of partial pressures in gas solubility and its implications
  • Examine case studies involving equilibrium constants in gas-liquid systems
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Students and professionals in physical chemistry, particularly those focusing on thermodynamics and gas solubility, as well as anyone involved in environmental science related to aquatic oxygen levels.

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Homework Statement


The equilibrium concentration of oxygen in fresh water exposed to the atmosphere is given for two temperatures. At 15 degrees celsius equilib [O2]= 630μmol/L at 25 degrees celsius equiln [O2]= 517μmol/L

The expression for the equilibrium constant, K, between the oxygen in the gas phase and in solution is given by K=[O2]/PO2/atm. Where pO2 is the partial pressure of atmospheric oxygen.

I need to calculate the enthalpy of dissolution, I figured I need to use the integrated Vant hoof equation.
But how do I figure out the partial pressues of oxygen so I can calculate the equilibrium constants?

[Thank you
 
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Partial pressure of oxygen is the fraction of pressure exerted by atmospheric oxygen. And since the Partial pressure is not going to change whether the oxygen dissolves or not, you don't require the use of oxygen's partial pressure.

You may write simply, K = [O2]. Now just use Van't Hoff's Equation.
 
Thanks.

I do not understand why I don't have to use the partial pressure, when it is in the expression for Kp. Is this the case for any equilibrium constant involving kp=[x]/Po2/atm?
 

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