Physical meaning of the equation E = - del V

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SUMMARY

The equation E = -∇V defines the electric field (E) as the negative gradient of the electric potential (V). This relationship indicates that the electric field is a vector perpendicular to the equipotential surfaces, with its magnitude representing the rate of change of potential in that direction. The discussion emphasizes that this concept can be visualized using topographical maps, where the gradient corresponds to the direction a ball would roll down a slope. The relationship is further clarified by relating it to force and potential energy, demonstrating that the mathematics of electric fields mirrors that of gravitational fields.

PREREQUISITES
  • Understanding of electric fields and potential energy
  • Familiarity with vector calculus, specifically gradients
  • Knowledge of the relationship between force and potential energy
  • Basic concepts of electrostatics, including capacitors
NEXT STEPS
  • Study the mathematical derivation of E = -∇V in electrostatics
  • Explore the concept of electric field lines and equipotential surfaces
  • Learn about the behavior of electric fields in parallel plate capacitors
  • Investigate the similarities between electric fields and gravitational fields
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Physics students, electrical engineers, and anyone seeking to deepen their understanding of electrostatics and the relationship between electric fields and potential energy.

Flying_Dutchman
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The gradient of a function gives a vector perpendicular to it's surface. So the equation reads electric field is the negative of the vector perpendicular to the equipotential surface. I know electric field and understand potential but I can't physically make sense for the above sentence how LHS is equal to RHS.
Hope anyone will answer .Thank you !
 
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It’s a definition. You may be able to visualize the relationship if you consider a standard topographical map as a two-dimensional analogy: the gradient of the altitude is a vector perpendicular to the contour lines of equal height, and it points in the direction that a ball at that point will naturally roll.
 
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The gradient does not just give any random vector which is perpendicular to the equipotential surface, but specifically the vector whose magnitude is equal to the rate of change of the function in that direction. So perhaps it is a little easier to understand:

The electric field is a vector whose direction is normal to the equipotential surface and whose signed magnitude is equal to the negative rate of change of the potential in that direction.
 
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Flying_Dutchman said:
I know electric field and understand potential but I can't physically make sense for the above sentence how LHS is equal to RHS.

Start by looking at an ideal parallel plate capacitor. What is the relationship between the voltage difference between the plates and the electric field between the plates?
 
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Nugatory said:
It’s a definition.
Not in the way it's usually presented in introductory college-level physics textbooks and courses. Field is defined as force per unit charge and potential is defined as potential energy per unit charge. From there the relationship between field and potential is derived.
 
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Flying_Dutchman said:
The gradient of a function gives a vector perpendicular to it's surface. So the equation reads electric field is the negative of the vector perpendicular to the equipotential surface. I know electric field and understand potential but I can't physically make sense for the above sentence how LHS is equal to RHS.
Hope anyone will answer .Thank u !

I often do not understand this type of question, because you essentially have accepted this in another form. Let me prove it to you.

Multiple both sides by a charge q that is in this E and V fields, i.e. you get

qE = - ∇qV

which is nothing more than

F = - ∇U

where F is the force acting on the charge q, and U is the potential energy. This is the general relationship between the force and the potential energy, i.e. force is the gradient of potential energy field.

Now, do you have a problem having an understanding or a visual picture of this, because you have accepted this already when it is applied to kinematics, such as force in a gravitational field. There is nothing different here, with the mathematics being identical to each other.

Zz.
 

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