Physics 11 question - its probs rly easy

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Homework Help Overview

The discussion revolves around a physics problem involving the change in momentum of a 7.0 kg object that accelerates uniformly over a distance of 21 meters in 4.2 seconds. Participants are exploring the relationship between force, mass, velocity, and momentum in the context of kinematics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants are examining the calculation of final velocity and its relation to average velocity. There is a focus on understanding how to derive final velocity from the given distance and time, as well as clarifying the distinction between average and final velocities.

Discussion Status

Some participants have provided guidance on using kinematic equations to find the final velocity, while others are questioning the original poster's assumptions about the final velocity being equal to the average velocity. The discussion is ongoing, with multiple interpretations being explored.

Contextual Notes

There is a mention of a discrepancy between the original poster's calculated momentum and the answer provided in the textbook, prompting further investigation into the correct approach to finding final velocity.

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Physics 11 question -- its probs rly easy !

Homework Statement



A horizontal force applied to a 7.0 kg object initially at rest causes it to accelerate uniformly and travel a distance of 21m in 4.2s. What is the change in momentum of the object?

Homework Equations



p = mv

The Attempt at a Solution



Heres what i did but got it wrong:

p=mv
=(7.0kg)(0 m/s)
= 0
p=mv
=(7.0kg)(5m/s)
= 35

so the answer should be 35 ya?
but the answer in the back of the book is 70 kg x m/s
help??
 
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You mistakenly considered its final velocity to be 5m/s. That is it's average velocity computed over the 21 meter distance in 4.2 seconds. What is its final velocity after 4.2 seconds?
 


Check the calculation of the final velocity.
 


PhanthomJay said:
You mistakenly considered its final velocity to be 5m/s. That is it's average velocity computed over the 21 meter distance in 4.2 seconds. What is its final velocity after 4.2 seconds?

how do you find final velocity then?
 


You will need to use a kinematic equation to find the final velocity.
 


Distance = Average velocity * time
Average velocity = (u + v)/2
 


so once i have the average velocity how do i find th final velocity?
 


Think about what the average velocity actually is. It is an average of two velocities together. What are those two velocities?
 

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