Physics 12 energy, work question

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The discussion focuses on calculating the time it takes for a bullet to stop after penetrating a sandbag and the average force acting on it. The bullet, weighing 12 grams and traveling at 860 m/s, penetrates 24 cm into the sand. The initial approach using momentum change (∇p=Ft) was corrected by applying kinematics equations to determine acceleration and time. The final calculations yield a stopping time of 5.6 x 10^-4 seconds and an average force of 18490 N acting on the bullet.

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gdhillon
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Q:A sandbag stops a 12 g bullet which was traveling at 860 m/s. The bullet penetrated a
distance of 24 cm into the sand?
a) How long did it take the bullet to stop?
b) What average force acted on the bullet?
first i used ∇p=Ft so 10.32=18490t t=5.6*10^-4 sec
then i put that into e=1/2mv^2 (to get letter A) so 1/2(.012)860^2= 4437.6
 
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gdhillon said:
first i used ∇p=Ft so 10.32=18490t
Where did the 18490 come from? The data tells you neither F nor t, only distance.
 
You know the distance traveled by the bullet, it's initial velocity, and it's final velocity. Use a kinematics equation which relates them to find out the acceleration of the bullet. Now use that to find the time it travels for using another kinematics equation. And then use that to calculate the average force using the formula you wrote.
 

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