Physics help Speed/ Acceleration question

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SUMMARY

The discussion focuses on a physics problem involving speed and acceleration. A driver initially traveling at 1.71 m/s accelerates at a constant rate of 0.076 m/s² over a distance of 9.97 km. The final speed is calculated using the formula V = √[Vi² + 2ax], resulting in a speed of 38.97 m/s. This calculation demonstrates the application of kinematic equations in solving real-world motion problems.

PREREQUISITES
  • Understanding of basic kinematics
  • Familiarity with the equation of motion V = √[Vi² + 2ax]
  • Knowledge of units of measurement in physics (m/s, m/s², km)
  • Ability to perform calculations involving square roots and multiplication
NEXT STEPS
  • Study advanced kinematic equations for varying acceleration
  • Learn about the implications of acceleration on vehicle dynamics
  • Explore real-world applications of physics in automotive engineering
  • Investigate the effects of friction and drag on acceleration
USEFUL FOR

This discussion is beneficial for physics students, automotive engineers, and anyone interested in understanding the principles of motion and acceleration in practical scenarios.

ashurina
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While driving from a city, a man gets stuck at 1.71 m/s behind a slow driver. He finally gets a passing lane, hits the gas and speeds up with a constant acceleration of 0.076 m/s^2 what is his speed in (m/s) after accelerating for 9.97 km?
 
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What have you tried so far?
 
I figured it out finally, this was a tough one but i got it

V = √[Vi² + 2ax] = √[1.71² + 2*.076*9970] = 38.97 m/s
 

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