Physics + Logic = tired brain :biggrin:

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Homework Help Overview

The discussion revolves around a physics problem involving forces, specifically comparing the ability to push a car along a flat road versus lifting it. The subject area includes concepts of friction and gravity.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the differences between the forces acting on the car when pushing versus lifting. Questions are raised about the direction of these forces and the role of friction compared to gravity.

Discussion Status

Some participants have offered guidance regarding the forces involved, including the equations for friction and gravity. There is an ongoing exploration of how these forces interact, but no consensus has been reached yet.

Contextual Notes

Participants note the importance of the coefficient of friction and the normal force in understanding the problem. There is also mention of estimating values, indicating potential constraints in the information available.

kristen151027
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This one should be quick and easy, but I just can't seem to get it:

"A college rower can easily push a small car along a flat road, but she cannot lift the car in the air. Since the mass of the car is constant, how can you explain this discrepancy?"

Edit: I'm thinking that friction can be overcome more easily than gravity...but I'm struggling to prove that.
 
Last edited:
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Think about the forces that are acting. What is the difference in direction between lifting it up, and pushing it across?
What are the forces acting in these directions?
 
Sorry, just read your edit... remember friction force is given by mu * N
(normal force). Where mu is the co-efficient of friction - you might be able to estimate this, or find an approximate value somewhere.
The force acting due to gravity is F=mg.
I hope this gives you enough to go on with...
 
tyco05 said:
Sorry, just read your edit... remember friction force is given by mu * N
(normal force). Where mu is the co-efficient of friction - you might be able to estimate this, or find an approximate value somewhere.
The force acting due to gravity is F=mg.
I hope this gives you enough to go on with...

Yes, thank you! :biggrin:
 
The force to lift the car up is [itex]F = m.g[/itex].
The force to push the car along a flat road is [itex]F > \mu_s.m.g[/itex]

Compare this two forces.

HINT: Between what values is usually [itex]\mu_s[/itex].
 
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