Physics Problem: Displacement, Acceleration, Velocity

Click For Summary
SUMMARY

The discussion focuses on calculating the acceleration, displacement, and average velocity of a skateboarder rolling down an 11.0 m ramp at a speed of 7.20 m/s. The skateboarder's acceleration is determined using the formula a = g sin(θ), where θ is the ramp's incline of 24.5°. Additionally, the average velocity is calculated as v = (vf - vi)/2, leading to the conclusion that the time taken to descend the ramp is 3.6 seconds. The discussion also addresses displacement and average velocity for a car traveling at 5 m/s along a square route with a side length of 20 m.

PREREQUISITES
  • Understanding of kinematic equations in physics
  • Knowledge of trigonometric functions, specifically sine and cosine
  • Familiarity with concepts of displacement and average velocity
  • Basic understanding of acceleration and its calculation
NEXT STEPS
  • Study the derivation of kinematic equations for uniformly accelerated motion
  • Learn how to apply trigonometric functions in physics problems
  • Explore the relationship between displacement and average velocity in two-dimensional motion
  • Investigate real-world applications of acceleration in sports physics
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding motion dynamics in real-world scenarios.

shawonna23
Messages
146
Reaction score
0
A skateboarder, starting from rest, rolls down a 11.0 m ramp. When she arrives at the bottom of the ramp her speed is 7.20 m/s.

(a) Determine the magnitude of her acceleration, assumed to be constant.

(b) If the ramp is inclined at 24.5° with respect to the ground, what is the component of her acceleration that is parallel to the ground?
 
Physics news on Phys.org
(a) Since the skateboarder is on an incline, a = g sinθ. To find the time it takes to descend, find the average velocity v = (vf - vi)/2. We know that t = distance/velocity, or in this case, 11/3.6. Using a = v/t, you can find that θ = ArcSin v/gt.

(b) If you draw a diagram of the problem you'll see that the x-component of acceleration is ax = a cos24.5
 
Last edited:
Average Velocity = (vf+vi)/2 and acceleration = (vf-vi)/t please could you explain how average velocity has been expressed as vf-vi over 2
 
Displacement Problem:
A car travels at a speed of 5 m/s along a square root ABCD find its displacement and average velocity from A to B, from A to C and from A to D i.e from A to all the corners with length of one side of the square is = 20 m.
Find dispacement and average velocity:
i- from A to B
ii- form A to C
iii- from A to D
 
Last edited:

Similar threads

  • · Replies 8 ·
Replies
8
Views
2K
Replies
16
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 38 ·
2
Replies
38
Views
4K
Replies
3
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K