Physics Problem; help me please

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A freight train with a mass of 15,000,000 kg is pulled by a constant force of 750,000 N, leading to a discussion on calculating the time to accelerate from rest to 85 km/h using Newton's second law. The acceleration is determined by dividing the force by the mass, resulting in 0.05 m/s². To find the time, the kinematic equation V(f) = V(i) + at is applied, but proper unit conversion from km/h to m/s is crucial. The correct conversion and calculations yield a time of 470 seconds, which contrasts with an incorrect initial calculation of 1700 seconds. Accurate unit handling is emphasized as essential for arriving at the correct answer.
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Help, I just can't seem to get this.

A freight train has a mass of 15000000 kg. If the locomotive can exert a constant pull (what is a constant pull?) of 750000 N, how long would it take to increase the speed of the train from rest to 85 km/h? (Disregard friction.)
 
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Newtons second law: f=ma, a=f/m. You can use this to derive the acceration and use some kinematics formulas to find out how long it will take to reach a certain velocity with a known acceleration and a known initial velocity.
 
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F = ma

750000 N = (15000000 kg) * a
 
Well, you have a fairly basic question that comes from Netwon's second law of motion. By constant pull, the system has a constant force that is pulling the train along. This means that the system also has constant acceleration, which is given by Netwon's Laws.

F = M A

You can easily find this acceleration by using the values already given.
You now can use this in a kinematics equation. You have acceleration,initial velocity,final velocity, and you need to find time.

I suggest using this equation:

V(f)=V(i)+at

By the way, make sure you watch your units. The final velocity that the problem gives is in kilometers per hour. Convert this speed to standard units.

Hope this helps
 
Ok... What is the answer? The book says 470 seconds. I did 750000N/15000000 and got .05m/s squared for the acceleration. Then, If I divide the final speed, 85 km/h by this acceleration, I get 1700 seconds which is wrong. How do they get 4.7 times 10 to the second (470 seconds)? Help please. I appreciate it.
 
conversion from m/s to km/h
 
They are looking for time in this problem.
 
yeah, but the conversion from m/s to km/h is essential in arriving at the proper time. You are dividing 85 km/h by m/s. The units do not cancel out.
 
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