Physics Problem; help me please

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SUMMARY

The discussion centers on calculating the time required for a freight train with a mass of 15,000,000 kg to accelerate from rest to a speed of 85 km/h, given a constant pull of 750,000 N. Using Newton's second law (F = ma), the acceleration is determined to be 0.05 m/s². The correct kinematic equation to find time is V(f) = V(i) + at, which requires converting the final speed from km/h to m/s. The correct answer is 470 seconds, achieved by properly applying unit conversions and kinematic principles.

PREREQUISITES
  • Understanding of Newton's second law of motion (F = ma)
  • Familiarity with kinematics equations, specifically V(f) = V(i) + at
  • Ability to convert units between kilometers per hour and meters per second
  • Basic knowledge of acceleration and its calculation
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  • Learn how to convert units between km/h and m/s effectively
  • Study more about kinematic equations and their applications in physics
  • Explore real-world applications of Newton's laws in transportation systems
  • Practice solving problems involving forces, mass, and acceleration
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the principles of motion and acceleration in real-world scenarios.

mike98020205
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Help, I just can't seem to get this.

A freight train has a mass of 15000000 kg. If the locomotive can exert a constant pull (what is a constant pull?) of 750000 N, how long would it take to increase the speed of the train from rest to 85 km/h? (Disregard friction.)
 
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Newtons second law: f=ma, a=f/m. You can use this to derive the acceration and use some kinematics formulas to find out how long it will take to reach a certain velocity with a known acceleration and a known initial velocity.
 
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F = ma

750000 N = (15000000 kg) * a
 
Well, you have a fairly basic question that comes from Netwon's second law of motion. By constant pull, the system has a constant force that is pulling the train along. This means that the system also has constant acceleration, which is given by Netwon's Laws.

F = M A

You can easily find this acceleration by using the values already given.
You now can use this in a kinematics equation. You have acceleration,initial velocity,final velocity, and you need to find time.

I suggest using this equation:

V(f)=V(i)+at

By the way, make sure you watch your units. The final velocity that the problem gives is in kilometers per hour. Convert this speed to standard units.

Hope this helps
 
Ok... What is the answer? The book says 470 seconds. I did 750000N/15000000 and got .05m/s squared for the acceleration. Then, If I divide the final speed, 85 km/h by this acceleration, I get 1700 seconds which is wrong. How do they get 4.7 times 10 to the second (470 seconds)? Help please. I appreciate it.
 
conversion from m/s to km/h
 
They are looking for time in this problem.
 
yeah, but the conversion from m/s to km/h is essential in arriving at the proper time. You are dividing 85 km/h by m/s. The units do not cancel out.
 

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