1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Physics problem involving displacement of car!

  1. May 24, 2012 #1
    1. The problem statement, all variables and given/known data

    A car is driven east for a distance of 48 km, then north for 25 km, and then in a direction 33° east of north for 29 km. Determine (a) the magnitude (in km) of the car's total displacement from its starting point and (b) the angle (from east) of the car's total displacement measured from its starting direction.



    2. Relevant equations
    magnitude is sort of a^2+b^2
    direction is tan theta = ay/ax


    3. The attempt at a solution
    I got part a right by finding magnitude of "R" which was sqrt of 62.5^2+50.11^2= 80.11 km i just can't seem to get part b right. i know it is north of east but whenever i do inverse tan of 50.11/62.5 i get 38.72 degrees which is wrong, HELP please
     
  2. jcsd
  3. May 25, 2012 #2

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    welcome to pf!

    hi wbetting! welcome to pf! :smile:
    no you didn't, you just got close

    you used 30° instead of 33° ! :redface:
     
  4. May 25, 2012 #3
    It marked it right on my online homework. Any idea how to do part b?
     
  5. May 25, 2012 #4

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    but you used 30° instead of 33° ! :cry:
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Physics problem involving displacement of car!
Loading...