Physics problem to fine average force

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To calculate the average force acting on a dummy during a crash test, the initial velocity of the car is 11 m/s, and the dummy moves 0.81 m before stopping. The equation v^2 = u^2 + 2as can be used to find acceleration, where v is the final velocity (0 m/s), u is the initial velocity (11 m/s), and s is the displacement (0.81 m). After determining acceleration, Newton's second law (F = ma) can be applied to find the net force, requiring the mass of the dummy (57 kg). The discussion emphasizes the need to incorporate mass into the calculations for accurate results.
rachels5
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A set of crash tests consists of running a test car moving at a speed of 11 m/s (24.2 m/h) into a solid wall. Strapped securely in an advanced seat belt system, a 57 kg (125.4 lbs) dummy is found to move a distance of 0.81 m from the moment the car touches the wall to the time the car is stopped. Calculate the size of the average force which acts on the dummy during that time.

I do not get this question, i have been working on it for days but i am extremely frustrated

I used the equation
v^2 + u^2 = 2as

where v = final velocity, u = initial velocity, a = acceleration, s = displacement.
so i said
0^2 + 11^2=2(a)(0.81)
It gave me the wrong answer.
but i think that i have to use mass, and my teacher has not shown me a formula in which mass is included
 
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Show what you've done and where you are stuck.

Hints: You can solve this using energy methods (consider the work done by the wall) or kinematics (find the average acceleration).
 
can you answer it now .
 
rachels5 said:
I used the equation
v^2 + u^2 = 2as
That should be v^2 = u^2 + 2as.

where v = final velocity, u = initial velocity, a = acceleration, s = displacement.
so i said
0^2 + 11^2=2(a)(0.81)
It gave me the wrong answer.
That will give you the acceleration. Then use Newton's 2nd law to find the net force. (Yes, you'll need the mass.)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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