an accident occurs up ahead on the highway. a driver travelling at 120km/h [e] reacts in 0.20s and applies the brakes causing an acceleration of 8.0m/s2 [w]. show that the stopping distance is 76 m.
what am i doing wrong? i changed the acceleration to match the directions, so i made it negative. but i am not getting the right answer.
d = vi * t + 0.5(a * t^2)
The Attempt at a Solution
i attempted this by using:
d = (120km/h / 3.6[e])(0.20s) + 0.5(-8.0m/s[e] * 0.20s^2)
d = 6.5m?