Piecewise Function Homework: Solve Fourier Coefficient b1

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SUMMARY

The discussion focuses on determining the Fourier coefficient b1 for a specified piecewise function. The user initially defines the function as f(t) = 1 for 0 PREREQUISITES

  • Understanding of Fourier series and Fourier coefficients
  • Knowledge of piecewise functions and their definitions
  • Familiarity with periodic signals and their properties
  • Basic integration skills for calculating Fourier coefficients
NEXT STEPS
  • Review the calculation of Fourier coefficients for piecewise functions
  • Study the implications of altering time variables in periodic functions
  • Learn about the convergence of Fourier series for different function representations
  • Practice defining and analyzing piecewise functions in mathematical contexts
USEFUL FOR

Students studying Fourier analysis, mathematicians working with periodic functions, and educators teaching advanced calculus concepts.

DrOnline
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Homework Statement


Given the following periodic signal:
2ztbmu8.jpg


What is the Fourier coefficient b1.

I'm not asking for help with the Fourier series. I feel my integration is solid.

What I need help with is creating the correct function!

The Attempt at a Solution



I first declare t=5 as now to be t=0, and T=6 becomes t=2, etc. Am I allowed to do this? It also seems a bit iffy because the period starts at t=4...

f(t) =
1, 0<t<1
t, 1<t<2

This gives me, as far as I can tell, the correct values for 0<t<2, compared to the graph.

Unsure about the "t" function there...

I am doubting whether this is correct, me and a friend have done the series 4-5 times now using this function, and we get the wrong answer, so we think the function we wrote is wrong.

Can somebody help me make sense of this?
 
Physics news on Phys.org
f(t) =
1 for t in the interval of [1+4(t-1), 2+4(t-1)]
etc.
 
DrOnline said:

Homework Statement


Given the following periodic signal:
2ztbmu8.jpg


What is the Fourier coefficient b1.

I'm not asking for help with the Fourier series. I feel my integration is solid.

What I need help with is creating the correct function!

The Attempt at a Solution



I first declare t=5 as now to be t=0, and T=6 becomes t=2, etc. Am I allowed to do this? It also seems a bit iffy because the period starts at t=4...

f(t) =
1, 0<t<1
t, 1<t<2

Don't forget ##f(t)=0,~2<t<4##.

This gives me, as far as I can tell, the correct values for 0<t<2, compared to the graph.

Unsure about the "t" function there...

I am doubting whether this is correct, me and a friend have done the series 4-5 times now using this function, and we get the wrong answer, so we think the function we wrote is wrong.

Can somebody help me make sense of this?

I don't understand the ##1.5## on your picture. But if you calculate the FS for the above function on ##(0,4)## extended periodically, it will converge to the required graph. But the function you are using and the one given are not the same since they disagree for the same value of ##t##. One is a translated version of the other and the FS may not look the same.
 
The 1.5 is the average value of the interval from "my" 1 to 2, I wrote that to demonstrate how to calculate the average of the function value to a friend.

You tell me to not forget the interval between 2 and 4, but they do not matter, because they will integrate to zero, this is how I see it. I know it is an inaccurate way when I describe the piecewise function, but I only listed the ones relevant for the FS. I do account for them in the period variables when I do the calculations.

My task is only to find the Fourier coefficient b1, so I don't know if that is affected by me messing with the times.

Tomorrow I think I will re-do this and using the times actually on the paper, use the first period, 1 to 4.

f(t)=
0, 0<t<1
1, 1<t<2
-1+t, 2<t<3
0, 3<t<4

I think I understand what you mean about messing with the times, perhaps it make the actual FS not match the actual graph as asked for in the task.
 

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