Pistons and pressure question help

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Homework Help Overview

The discussion revolves around calculating average pressure exerted on pistons given specific forces and areas. The subject area includes concepts of pressure, force, and area in the context of fluid mechanics or physics involving pistons.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore how to calculate average pressure, questioning whether to combine areas of multiple pistons or treat them individually. Some express confusion regarding the term "average" in relation to pressure calculations.

Discussion Status

The discussion is ongoing, with participants sharing their interpretations and calculations. Some guidance has been offered regarding the relationship between force and pressure, but no consensus has been reached on the correct approach to the problem.

Contextual Notes

There are indications of confusion regarding the definitions and implications of average pressure, as well as the treatment of multiple pistons in calculations. Participants are also navigating the specifics of the problem setup and the information provided.

lollol
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area of a piston is 0.02

what is the AVERAGE pressure exerted on 2 equal pistons if the force is 25 N

P = F/A

do you just combine the areas.. and divide the combined area by F

i just did... pressure = F/Area of 1 piston

and since it said average... they both give the same pressure.. add them up.. divide by two, and end up with the same pressure. Is this wrong?

I didn't combine the areas
 
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can you write out the entire, complete question?
 
The force exerted on 2 pistons was 10 N.. let's say
Area of each piston is 2m

What was the average pressure on the pistons? The word average confused the heck out of me...

so I found the pressure on each... added them.. divided by 2... and got the same pressure

Was I supposed to add the two areas?
 
think about it. what has changed?

if you were to divide pressure by half then you must also divide F/a by half as well otherwise the equation won't work. if you do that then nothing has changed and your getting no where.

and just to give you an even bigger hint: force isn't changing either.

hope this helps
 

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