Plane immersed in the earth's vertically downward-pointing magnetic field

  • Thread starter syhpui2
  • Start date
  • #1
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Homework Statement




This question and the next two refer to this situation:

http://i.imgur.com/dgJMR.png

dgJMR.png


A passenger jet is flying over Alaska in level flight at a constant altitude h = 10 km and constant speed of v = 300 m/s, immersed in the earth's vertically downward-pointing magnetic field of B = 30 μT. The distance between the tips of the aircraft's metal wings is d = 50 m.

Part A:
Calculate the potential difference ε between the aircraft's wing tips due its motion through the earth's magnetic field.
(a) ε = 0.0 volts
(b) ε = 0.45 volts
(c) ε = 0.90 volts

Answer is B

Part B
Which wingtip has positive charge, as viewed by a passenger in the airplane who is facing in the direction that the airplane is traveling?
(a) the right wingtip
(b) the left wingtip
(c) neither wingtip

Answer is B



Homework Equations



emf = d flux / dt

flux = int[B*dA]

The Attempt at a Solution



For part A, I tried formula above, I get answer C, because I thought I need to calculate difference for both wings? Part B I used F=BIL, however, I get the force is on right wing? What is the relationship between force ans its direction of the plane that traveling?

Thx
 

Answers and Replies

  • #2
Delphi51
Homework Helper
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For part A, I used the generator formula V = L*v*B = 50*300*30x10^-6 = 0.45 Volts. Had I used only one wing length I would have gotten half that voltage.

Part B is not a formula question. Use hand rules to figure out which way the electrons are pushed. Then you can tell which side is negative and which is positive.
 
  • #3
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For part A, I used the generator formula V = L*v*B = 50*300*30x10^-6 = 0.45 Volts. Had I used only one wing length I would have gotten half that voltage.

Part B is not a formula question. Use hand rules to figure out which way the electrons are pushed. Then you can tell which side is negative and which is positive.
Everything makes sense now, thanks!
 

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