Plane's new velocity after wind from west

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SUMMARY

A plane traveling north at 200 meters/second experiences a wind from the west that accelerates it at 15 m/s² for 10 seconds. The resulting velocity due to the wind is calculated as 150 m/s towards the east. Using the Pythagorean theorem, the final velocity of the plane is determined to be 250 m/s, combining both the northward and eastward components. This calculation confirms the correct resultant velocity of the plane after the wind's influence.

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1. Homework Statement
A plane is traveling north at 200 meters/second; a wind blows from the west and accelerates the plane at 15m/s^2. If the wind lasts 10 seconds what is the plane's new velocity?

2. Homework Equations
velocity = acceleration*time

3. The Attempt at a Solution
v = (15m/s^2)(10s) = 150 m/s. Is that towards east? I tried doing Pythagorean theorem with 150 m/s as base and 200m/s as the vertical component since the plane was traveling north and got 132m/s for hypotenuse. But that's not one of the answer choices. ?
 
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jff0404 said:
1. Homework Statement
A plane is traveling north at 200 meters/second; a wind blows from the west and accelerates the plane at 15m/s^2. If the wind lasts 10 seconds what is the plane's new velocity?

2. Homework Equations
velocity = acceleration*time

3. The Attempt at a Solution
v = (15m/s^2)(10s) = 150 m/s. Is that towards east? I tried doing Pythagorean theorem with 150 m/s as base and 200m/s as the vertical component since the plane was traveling north and got 132m/s for hypotenuse. But that's not one of the answer choices. ?

Correct, the plane is blown east. Check your math. This is what I got for the hypotenuse.

[tex]v_{f}=\sqrt{200^{2}+150^{2}}=250\frac{m}{s}[/tex]
 
You're right! Thank you.
 

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