- 74

- 0

**1. Homework Statement**

Consider the eddy-current braking. A square loop, with 10 cm side is shot with the velocity 10 m/s into the uniform magnetic field with magnitude 0.1 T. The field is perpendicular to the plane of the loop, and the loop starts entering magnetic field at t=0. The resistance of the loop is 1.00 Ohm and the mass is 1.0 g. Assume the loop is moving to the right along x-axis and that x(t=0)=0. Find the velocity of the loop 0.1 seconds later. Comment on assumptions and approximation, or venture into the realm of differential equations…

**2. Homework Equations**

A = 0.1m X 0.1 m =

**0.01m**

^{2}V = 10m/s

B = 0.1T

R = 1Ω

m = 0.001kg

t = 0.1s

Flux = BA = 0.001Wb

ε = Flux/t = 0.01v

I = ε/R

l = 0.1m

**3. The Attempt at a Solution**

My first reflex was to find the current: I = .01v/1Ω = 0.01A

And then I wanted to find the new velocity with the formula above, problem is; IR/Bl = (0.01A X 1Ω)/(0.1T X .1m) = 10 m/s, so that doesn't work

And now I'm stumped, I can't really figure out this problem -_-