here is the problem image

http://tinypic.com/r/qxrqdu/5

Weight A is connected via a string to Weight B. Weight B is connected to a string to Weight C. Mass of A is 21 KG. Mass of B is 5 KG. Mass of C is 10 KG. the kinetic friction between the table and the 5 KG weight is 0.22

i got 2.75 M/S^2 for acceleration is that correct?

i need to know whats the tension in the string between A and B. include steps plz

turbo
Gold Member
Can you show and explain your work? There are lots of talented people here, but they are not allowed to do your homework for you.

• 1 person
Can you show and explain your work? There are lots of talented people here, but they are not allowed to do your homework for you.

well whats the point of this website?

I figured out the acceleration part but I cant figure out the Tension!

Chestermiller
Mentor
I figured out the acceleration part but I cant figure out the Tension!
To get the tension in the string between A and B, draw a free body diagram on A, and write down the Newton's 2nd Law force balance on A.

Ibix
2020 Award
As per the rules you agreed to when you created your account, you need to show your working so far before we will help.

well since we don't have an angle. then 210-ft= 2.75(5)
so 210-ft= 13.75

-ft = 13.75-210
ft= 196.25 ?
is that correct!

Chestermiller
Mentor
well since we don't have an angle. then 210-ft= 2.75(5)
so 210-ft= 13.75

-ft = 13.75-210
ft= 196.25 ?
is that correct!
No. If you are doing a force balance on weight A, shouldn't the 5kg on the right hand side of your equation be 21kg?

• 1 person
Can you show and explain your work? There are lots of talented people here, but they are not allowed to do your homework for you.

No. If you are doing a force balance on weight A, shouldn't the 5kg on the right hand side of your equation be 21kg?

correct my bad got confused. using different weights in one problem does not make sense either.

so 210-ft= 2.75(210)

I got ft= 367.5 ?

berkeman
Mentor
here is the problem image

http://tinypic.com/r/qxrqdu/5

Weight A is connected via a string to Weight B. Weight B is connected to a string to Weight C. Mass of A is 21 KG. Mass of B is 5 KG. Mass of C is 10 KG. the kinetic friction between the table and the 5 KG weight is 0.22

i got 2.75 M/S^2 for acceleration is that correct?

i need to know whats the tension in the string between A and B. include steps plz

You need to show your work on the problem before you may receive tutorial help here on the PF. Please check your PMs.

berkeman
Mentor
well whats the point of this website?

The point of this website is to help you learn how to learn. If we just spoon-feed you the answers, that will no help you to improve in your understanding of the subject, and will not help you to be able to figure out problems on your own (which is how real life works).

ok I showed my work for that part. can anyone tell me if 367.5 is correct?

Chestermiller
Mentor
correct my bad got confused. using different weights in one problem does not make sense either.

so 210-ft= 2.75(210)

I got ft= 367.5 ?
No. It's not 2.75(210), it's 2.75(21). Also, you did the algebra wrong. You have the right idea, but you gotta be more careful with the math.

Chet

No. It's not 2.75(210), it's 2.75(21). Also, you did the algebra wrong. You have the right idea, but you gotta be more careful with the math.

Chet

210-ft=57.75

ft=152.25 ???

Chestermiller
Mentor
Yes, provided your solution for the acceleration is correct.

Yes, provided your solution for the acceleration is correct.

how about the tension on the cord between A and B
ft=152.25 ???

Chestermiller
Mentor
how about the tension on the cord between A and B
ft=152.25 ???

That is what you calculated.

That is what you calculated.

yes.

21KG(10M/S^2) -FT= ma
210-FT=21(2.75)
FT=152.25

That is what you calculated.

yes.

21KG(10M/S^2) -FT= ma
210-FT=21(2.75)
FT=152.25

so? is it correct or not!

Chestermiller
Mentor
so? is it correct or not!
Yes.