MHB Please find the side length of an equilateral triangle

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To find the side length of an equilateral triangle ABC with an inner point P, given distances PA=4, PB=5, and PC=3, a rotation of the triangle by 60 degrees around point C is utilized. This rotation positions point P' such that angle P'PA becomes 90 degrees, creating triangle CPA with angle CPA measuring 150 degrees. Using the known lengths and angles, the side length AC can be calculated. The solution effectively demonstrates how geometric transformations can simplify complex problems. The method highlights the relationship between the inner point and the triangle's vertices.
Albert1
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P is an inner point of equilateral triangle ABC ,
given PC=3, PA=4,PB=5 ,please find the side length of the equilateral triangle
 
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Albert said:
P is an inner point of equilateral triangle ABC ,
given PC=3, PA=4,PB=5 ,please find the side length of the equilateral triangle
Rotate the trianlge by 60 degrees about the point C. Let $P'$ be the new position of $P$. Then $\angle P'PA=90$. Thus we get a triangle $CPA$ with $\angle CPA=150$ and $PC=3, PA=4$. To find $AC$.
 

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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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