Another1
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The discussion revolves around the method of reduction of order in solving differential equations, specifically focusing on the transformation of a second-order differential equation into a first-order equation. Participants explore the implications of substituting a function into the equation and the resulting mathematical manipulations.
The discussion appears to be exploratory with no clear consensus reached. Participants build upon each other's contributions but do not explicitly agree on a single approach or solution.
Participants do not clarify all assumptions made during the derivations, and the discussion includes various steps that may depend on specific definitions or interpretations of the functions involved.
y'' = uv'' +2u'v'+ u''vCountry Boy said:What have you tried? If y= uv then what is y'? What is y''? What do you get when you put those into the differential equation? And then use the fact that u itself satisfies the equation, that u''+ V(x)u= 0.
Okay, and since u satisfies u''+ Vu= 0, that isAnother said:y'' = uv'' +2u'v'+ u''v
so
y''+ Vy = uv'' +2u'v'+ u''v + Vuv = 0