Please help me, really frustrated, question is due @ 11:59 tonight

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SUMMARY

The discussion centers on calculating the charge value (q) that would equate the gravitational force between Earth and the moon to the electrostatic force between them. The gravitational force is represented by the equation F_gravity = G(m_1*m_2)/r^2, while the electrostatic force is represented by F_electric = k(q_1*q_2)/r^2. The user has attempted various values for q, including 1.6e-19 and 8.99e10, but has not succeeded. The correct approach involves setting these two forces equal and solving for q.

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chrish
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hi, thanks for helping me.

heres the question

Suppose the moon had a net negative charge equal to -q and Earth had a net positive charge equal to +10q. What value of q would yield the same magnitude force that you now attribute to gravity?

(answer in coulombs) I have it on a thing called webassign, and you can only have 15 tries... i used 14. here are my wrong attempts:
1.6e-19
1.6e-18
-1.6e-18
-1.6e-20
1.6e-20
1.6e18
8.99e10
-8.99e10
.1
-.1
8.99e9
-8.99e9
-8.99e8
-10
 
Last edited:
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https://www.physicsforums.com/showthread.php?t=94379

We will not do your homework for you, we will only help. Did you read the guidelines?
 
The gravitational attraction must equal the electrostatic attraction
[tex]\frac{Gm_em_m}{r^2} \ = \ \frac{kq_1q_2}{r^2}[/tex]
 

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