Plotting Complex Region: y > 0

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SUMMARY

The discussion centers on plotting the complex region defined by the inequality \(\left| \frac{z + i}{z - i} \right| > 1\). The user successfully simplifies this to the condition \(y > 0\) after manipulating the equation \(\left|z+i \right| > \left| z - i \right|\) and deriving the inequality \(4y > 0\). This confirms that the region of interest is indeed the upper half-plane where \(y\) is positive. The user expresses uncertainty about their conclusion but has correctly identified the region to plot.

PREREQUISITES
  • Understanding of complex numbers and their representation as \(z = x + iy\)
  • Familiarity with inequalities involving absolute values in the complex plane
  • Knowledge of geometric interpretations of complex inequalities
  • Basic skills in algebraic manipulation and rearranging equations
NEXT STEPS
  • Explore the geometric interpretation of complex inequalities in the complex plane
  • Learn about the implications of the inequality \(\left| z + i \right| > \left| z - i \right|\)
  • Study the properties of complex functions and their mappings
  • Investigate additional examples of plotting complex regions defined by different inequalities
USEFUL FOR

Students studying complex analysis, mathematics educators, and anyone interested in visualizing complex regions and inequalities in the complex plane.

Mechdude
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Homework Statement


i was supposed to figure out what this region looks like ad to plot it
[tex]\left| \frac{z + i}{z - i} \right| > 1[/tex]



Homework Equations



[itex]z = x + iy[/itex]


The Attempt at a Solution



i tried a couple of rearrangements but i got nowhere:
[tex]\left|z+i \right| > \left| z - i \right|[/tex]
getting:
[tex]\sqrt{ x^2 + (y+1)^2 } > \sqrt{ x^2 + (y-1)^2 }[/tex]

which ends up [tex]4y > 0[/tex]
is this it? simply y>0?
 
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i think, I am not sure, but try something like this

|a| > |b|

=> a > |b| or a < -|b|

=> -a < b < a or a < b < -a

=> (b > -a and b < a ) or (b > a and b < -a)

and plot
 
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