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Pneumatic Cylinder to open Hatch

  1. Feb 3, 2009 #1
    Hey everyone,

    Having a little trouble with something a little out of my element. I've been tasked to design a pneumatic system to open a ~500lb hatch. I think I'm leaning towards a pneumatic cylinder to act on a bell crank. I need the hatch to open to 110 degrees from zero in about 10 seconds.

    Where I'm getting stuck is on the force necessary to perform this action so I can size my cylinder and then the rest of the system. Any help would be greatly appreciated.
  2. jcsd
  3. Feb 3, 2009 #2


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    Science Advisor

    What is the layout like? You need to describe how the hatch is constrained and what it looks like. Diagrams are really helpful in these cases.
  4. Feb 9, 2009 #3
    1st of all calculate the acceleration

    acceleration can calculated by using equation of motion,

    aceeleration= 2ө/ (tXt)
    where ө= total angle travelled, (in your case it is 110 degrees)
    t= time taken for travelling the angle ө(in your case it is 10 sec.)

    torque, T= (inertia of the rotating object) X acceleration

    From th torque u can calculate the force required.....

    Force F=Tr, where r is the radial distance @ which u r rotating the object...
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