Point of intersection of 2 parametric lines

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SUMMARY

The discussion focuses on finding the point of intersection of two parametric lines defined as L1: x=-2t, y=1+2t, z=3t and L2: x=-9+5s, y=36+2s, z=1+5s. To solve for the intersection, users are advised to set the corresponding x, y, and z equations equal to each other, resulting in a system of three equations with two unknowns, s and t. By solving any two of these equations for s and t, users can verify consistency with the third equation to confirm the intersection point. This method ensures a systematic approach to solving parametric equations.

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Consider the two lines
L1: x=-2t y=1+2t z=3t and
L2: x=-9+5s y=36+2s z=1+5s
Find the point of intersection of the two lines.

My teacher said that I should use system of equations to solve for the point, but I am sort of confused on what to do because there are 2 variables. Is there something obvious that I am overlooking because this problem doesn't seem too hard. I tried making an equation containing t in terms of s and then plugging in the s for an x value, but I still get a wrong answer.
 
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Set x,y and z in L1 equal to x,y and z in L2. That gives you three equations in two the two unknowns s and t. Pick any two of them and solve for s and t. Is that consistent with the third equation? They are consistent. If you are getting a wrong answer can you show us how you got s and t and what you got?
 

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