- #1

goonking

- 434

- 3

## Homework Statement

Where does the line through (−2, 3, 2) and (3, 5, −1) intersect the plane x + y − 2z = 6?

## Homework Equations

## The Attempt at a Solution

i used r = r0 + tv

the vector between the 2 given points is <5,2,-3>

r = (-2,3,2) + t<5,2-3>

x = -2 + 5t y=3+2t z=2 - 3t

plugging these into the plane given: -2+5t + 3+2t -2(2-3t)= 6

solving for t , t should equal 9/13 if my algebra is correct.

plugging into the parametric equations , the point of intersection should be (19/13 , 57/13, -1/13)

can someone check all this?