Pointwise Conv. | Does $f_{n}$-$f$ -> 0 for Each x?

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SUMMARY

Pointwise convergence of a sequence of functions \( f_n \) to a function \( f \) is defined such that for each \( x \) in the specified domain, the limit \( |f_n(x) - f(x)| \to 0 \) as \( n \to \infty \). This means that for every point \( x \), the difference between the sequence \( f_n(x) \) and the function \( f(x) \) approaches zero. The discussion confirms that pointwise convergence directly implies this condition for all \( x \) in the domain.

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Does pointwise convergence mean that |$f_{n}$-$f$|->0 for each x?
 
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Fermat said:
Does pointwise convergence mean that |$f_{n}$-$f$|->0 for each x?
Yes. More precisely, it means that for each $x$ (in some specified domain) $|f_n(x) - f(x)| \to0$ as $n\to\infty$.
 
Fermat said:
Does pointwise convergence mean that |$f_{n}$-$f$|->0 for each x?

Wellcome back to MHB Fermat!... yes, pointwise convergence to f(x) means that $\lim_{n \rightarrow \infty} |f_{n} (x) - f(x)| = 0$ for any x in the domain...

Kind regards

$\chi$ $\sigma$
 

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