MHB Pointwise Conv. | Does $f_{n}$-$f$ -> 0 for Each x?

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Does pointwise convergence mean that |$f_{n}$-$f$|->0 for each x?
 
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Fermat said:
Does pointwise convergence mean that |$f_{n}$-$f$|->0 for each x?
Yes. More precisely, it means that for each $x$ (in some specified domain) $|f_n(x) - f(x)| \to0$ as $n\to\infty$.
 
Fermat said:
Does pointwise convergence mean that |$f_{n}$-$f$|->0 for each x?

Wellcome back to MHB Fermat!... yes, pointwise convergence to f(x) means that $\lim_{n \rightarrow \infty} |f_{n} (x) - f(x)| = 0$ for any x in the domain...

Kind regards

$\chi$ $\sigma$
 
We all know the definition of n-dimensional topological manifold uses open sets and homeomorphisms onto the image as open set in ##\mathbb R^n##. It should be possible to reformulate the definition of n-dimensional topological manifold using closed sets on the manifold's topology and on ##\mathbb R^n## ? I'm positive for this. Perhaps the definition of smooth manifold would be problematic, though.

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