Polarisation (light on water surface)

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SUMMARY

The discussion centers on the behavior of polarized light when viewed through a Polaroid filter. As the student rotates the filter, the puddle of water appears alternately darker and lighter due to the alignment of the filter with the plane of polarization of the reflected light. When the filter is aligned with the plane of polarization, the light is absorbed, making the puddle appear darker. Conversely, when the filter is perpendicular to the plane of polarization, the light passes through, causing the puddle to appear brighter. This understanding aligns with the principles of light polarization and the characteristics of Polaroid filters.

PREREQUISITES
  • Understanding of light polarization
  • Knowledge of Polaroid filter mechanics
  • Familiarity with the concept of glare and reflection
  • Basic principles of wave optics
NEXT STEPS
  • Study the physics of light polarization in detail
  • Explore the properties and applications of Polaroid filters
  • Learn about the interaction of light with surfaces, particularly in optics
  • Investigate the mathematical modeling of polarized light behavior
USEFUL FOR

Students studying optics, physics educators, and anyone interested in the practical applications of polarized light in photography and visual technologies.

ravsterphysics
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Homework Statement


A student looks at the sunlight reflected off a puddle of water. She puts a polarising (Polaroid) filter in front of her eye. As she rotates the filter the puddle appears darker then lighter.

Explain this observation

Homework Equations

The Attempt at a Solution


Here's my answer:

"As the student rotates the filter so it is in the same plane of polarisation of the polarised light, the wave will be absorbed (ie blocked) thus the puddle will appear darker.

And when it is rotated so it is perpendicular to the plane of polarisation of the reflected wave, the wave is no longer absorbed so the glare remains and the puddle will appear brighter''
----

But according to the mark scheme this would be wrong because ''When planes are parallel puddle appears light OR when perpendicular puddle appears dark''

where have i gone wrong? since the light is reflected horizontally, wouldn't the filter that is perpendicular to the light NOT block out the light, thus making the puddle appear brighter? (because the glare remains)
 
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ravsterphysics said:

Homework Statement


A student looks at the sunlight reflected off a puddle of water. She puts a polarising (Polaroid) filter in front of her eye. As she rotates the filter the puddle appears darker then lighter.

Explain this observation

Homework Equations

The Attempt at a Solution


Here's my answer:

"As the student rotates the filter so it is in the same plane of polarisation of the polarised light, the wave will be absorbed (ie blocked) thus the puddle will appear darker.

And when it is rotated so it is perpendicular to the plane of polarisation of the reflected wave, the wave is no longer absorbed so the glare remains and the puddle will appear brighter''
----

But according to the mark scheme this would be wrong because ''When planes are parallel puddle appears light OR when perpendicular puddle appears dark''

where have i gone wrong? since the light is reflected horizontally, wouldn't the filter that is perpendicular to the light NOT block out the light, thus making the puddle appear brighter? (because the glare remains)
I think you have the concept right, but it is probably just a convention in how the "direction" of the polarizer is defined. I'm most familiar with saying that light that is polarized in the same direction as the polarizer makes it through. But you are correct that the physical stretching/alignment of a Polaroid filter is the direction that absorbs the light. Have a look at this wikipedia page, for example:

https://en.wikipedia.org/wiki/Polarizer
 
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berkeman said:
I think you have the concept right, but it is probably just a convention in how the "direction" of the polarizer is defined. I'm most familiar with saying that light that is polarized in the same direction as the polarizer makes it through. But you are correct that the physical stretching/alignment of a Polaroid filter is the direction that absorbs the light. Have a look at this wikipedia page, for example:

https://en.wikipedia.org/wiki/Polarizer

polarized_ligth_water_reflection.jpg


Okay using the above information, is this valid:

"Since reflected light is horizontally polarised, if the polaroid is oriented so it is perpendicular to the plane of the reflected light, the puddle will appear darker because the reflected light has been absorbed, ie blocked, because only light that is in the same direction as the polaroid is allowed through.

Whereas when the polaroid is oriented so it is parallel to the reflected light, the glare remains because the reflected light is in the same plane as the polaroid so it is let through thus the puddle appears brighter."
 
ravsterphysics said:
polarized_ligth_water_reflection.jpg


Okay using the above information, is this valid:

"Since reflected light is horizontally polarised, if the polaroid is oriented so it is perpendicular to the plane of the reflected light, the puddle will appear darker because the reflected light has been absorbed, ie blocked, because only light that is in the same direction as the polaroid is allowed through.

Whereas when the polaroid is oriented so it is parallel to the reflected light, the glare remains because the reflected light is in the same plane as the polaroid so it is let through thus the puddle appears brighter."
The way I read the wiki article, when the plane of the polarized light is parallel to the stretched direction of the Polaroid film, it is absorbed.
 
berkeman said:
Stretching of the sheet during manufacture causes the PVA chains to align in one particular direction. Valence electrons from the iodine dopant are able to move linearly along the polymer chains, but not transverse to them. So incident light polarized parallel to the chains is absorbed by the sheet; light polarized perpendicularly to the chains is transmitted.
 

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