Index of refraction from reflected light (polarised)

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SUMMARY

The discussion focuses on calculating the index of refraction of an unknown liquid using the principles of polarized light and Brewster's angle. When light reflects off the liquid's surface at an angle of 54.30°, the reflected light is completely transmitted through a linear sheet polarizer aligned parallel to the interface. This indicates that the angle of incidence corresponds to Brewster's angle, which is critical for determining the refractive index of the liquid using the formula n = tan(θ), where θ is the Brewster angle.

PREREQUISITES
  • Understanding of Brewster's angle in optics
  • Knowledge of linear polarization of light
  • Familiarity with the concept of refractive index
  • Basic principles of light reflection and transmission
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  • Study the derivation of Brewster's angle and its applications in optics
  • Learn about the polarization of light and its interaction with different materials
  • Explore the mathematical relationship between angle of incidence and refractive index
  • Investigate practical experiments to measure the refractive index using polarized light
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Jon.G
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Homework Statement


A beam of light is reflected from the surface of some unknown liquid, and the light is examined with a linear sheet polarizer. It is found that when the central axis of the polariser (that is, the perpendicular to the plane of the sheet) is tilted down from the vertical at an angle of 54.30◦ , the reflected light is completely passed, provided the transmission axis is parallel to the plane of the interface. From this information, compute the index of refraction of the liquid.

Homework Equations

The Attempt at a Solution


Honestly, I'm having some trouble even just picturing this. The wording about the polariser confuses me a little.

I'm not sure where to start. My first thought is to go to Brewster's angle as this involves reflected light getting polarised, but I thought a condition for this was that Incident (or reflected) angle + transmitted angle = 90.
But if the transmission axis is parallel to the interface this would mean the light is normally incident, and this doesn't feel right (and even if it was I wouldn't know where to go from here)

Any help or hints appreciated.
 
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Jon.G said:

Homework Statement


A beam of light is reflected from the surface of some unknown liquid, and the light is examined with a linear sheet polarizer. It is found that when the central axis of the polariser (that is, the perpendicular to the plane of the sheet) is tilted down from the vertical at an angle of 54.30◦ , the reflected light is completely passed, provided the transmission axis is parallel to the plane of the interface. From this information, compute the index of refraction of the liquid.

Homework Equations

The Attempt at a Solution


Honestly, I'm having some trouble even just picturing this. The wording about the polariser confuses me a little.

I'm not sure where to start. My first thought is to go to Brewster's angle as this involves reflected light getting polarised, but I thought a condition for this was that Incident (or reflected) angle + transmitted angle = 90.
But if the transmission axis is parallel to the interface this would mean the light is normally incident, and this doesn't feel right (and even if it was I wouldn't know where to go from here)

Any help or hints appreciated.

The plane of the polarizer has to be perpendicular to the reflected beam, and its transmission axis is parallel to the interface, so perpendicular to the plane of incidence.
What do you know about the reflection of the parallel and perpendicular polarized light? Is it any angle of incidence when the whole reflected light is polarized perpendicularly to the plane of incidence, no matter of the polarization state of the incident light? The polarizer transmits the whole reflected intensity, if the reflected light is polarized parallel with the transmission axis of the polarizer. That happens at 54.3°angle of incidence.

polarizerbrewster.JPG
 

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