I Polarization of photons quantum mechanically

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Photon polarization from a quantum mechanical perspective is fundamentally tied to the spin component of the photon's quantum state, rather than being a process that alters a part of the photon. The concept of "unpolarized light" in classical terms translates to a collection of photons with random polarizations, but a single photon cannot be considered unpolarized. The polarization state of a photon is determined by its measurement, which can change the state if it is not already in an eigenstate of the measurement operator. The discussion emphasizes that polarization is an inherent property of the photon, not something that is added or modified through interaction. Therefore, understanding photon polarization requires recognizing it as an intrinsic aspect of the photon's quantum state.
sol47739
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I have some fundamental questions about the polarization of photons from the quantum mechanical perspective.
What is it of the photon that gets polarized from a quantum mechanical perspective? In the classical perspective it is often thought that it is the oscillating electric field that gets polarized. But in the quantum case: Is it the de Broglie wave function? Or is it the spin and in case it is the spin, how is the polarizing filter able to determine which kind of spin gets through? What is the polarizing filter made of incase it determines what kind of spin of the photons get’s through?
 
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sol47739 said:
What is it of the photon that gets polarized from a quantum mechanical perspective?
The question is unanswerable because it is based on a false assumption. A photon doesn't "get polarized" by acting on some part of it. Polarization is just the spin part of the photon's quantum state.

Thinking of what is classically called "unpolarized light" is not a good way to approach photon polarization in QED. Classical "unpolarized light", in quantum terms, is (highly heuristically) just a huge number of photons with random polarizations, so the total polarization is negligible. But there is no such thing as an "unpolarized" single photon.
 
PeterDonis said:
But there is no such thing as an "unpolarized" single photon.
But that is a bit too facile it seems to me. Absent some asymmetry (perhaps a filter) the description of the photon is basis dependent. In particular one can have RHCP and LHCP or X and Y .
PeterDonis said:
A photon doesn't "get polarized" by acting on some part of it.
The polarization of "the photon" will produce an answer that depends upon the question. In that sense one "acts upon it".
 
hutchphd said:
the description of the photon is basis dependent
The photon's state is not basis dependent. Its components might be, but that is true of any quantum system.

hutchphd said:
The polarization of "the photon" will produce an answer that depends upon the question.
You can change the polarization part of a photon's state by measuring its polarization, yes. But that's true of any quantum system: a measurement, unless it already happens to be in an eigenstate of the measurement operator, will change the state.

hutchphd said:
In that sense one "acts upon it".
Perhaps, but I don't think that's what the OP meant. The OP seemed to me to be thinking of polarization as something you "do" to some part of the photon. That's not correct. Polarization is, as I said, the spin part of the photon's state. Or, if you like, it's the spin degree of freedom of the photon. It's not something you "add on" to a photon by doing something to it: that spin degree of freedom is always there.
 
We often see discussions about what QM and QFT mean, but hardly anything on just how fundamental they are to much of physics. To rectify that, see the following; https://www.cambridge.org/engage/api-gateway/coe/assets/orp/resource/item/66a6a6005101a2ffa86cdd48/original/a-derivation-of-maxwell-s-equations-from-first-principles.pdf 'Somewhat magically, if one then applies local gauge invariance to the Dirac Lagrangian, a field appears, and from this field it is possible to derive Maxwell’s...