Polarization Prob | Reducing Intensity at 62° Angle

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SUMMARY

The discussion focuses on calculating the reduction in intensity of light passing through two polarizers oriented at a 62° angle. The relevant equation used is I = Io * Cos²(θ), where θ is the angle between the light's polarization direction and the polarizer's axis. The initial attempt yielded a 16% intensity reduction, but confusion arose regarding the light that does not pass through the first polarizer affecting the second. Clarification on the application of the equation is necessary for accurate results.

PREREQUISITES
  • Understanding of light polarization concepts
  • Familiarity with the equation I = Io * Cos²(θ)
  • Knowledge of how multiple polarizers interact with polarized light
  • Basic trigonometry for angle calculations
NEXT STEPS
  • Review the principles of light polarization and Malus's Law
  • Study the effects of multiple polarizers on light intensity
  • Practice problems involving different angles between polarizers
  • Explore simulations of light passing through polarizers for visual understanding
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Students studying optics, physics educators, and anyone interested in the practical applications of light polarization in technology and science.

Galahad43
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Homework Statement



Two polarizers are oriented at 62° to one another. Light polarized at a 31° angle to each polarizer passes through both. What reduction in intensity takes place?
___.%

Homework Equations


I=IoCos^2((-))


The Attempt at a Solution


Tried suing the above equation, and got 16%. I don't know how to deal with the fact that light that did not go through the first polarizer is hitting the second one> Please help. Thank you
 
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Galahad43 said:
Tried suing the above equation, and got 16%.
Sounds good to me.
I don't know how to deal with the fact that light that did not go through the first polarizer is hitting the second one
What do you mean?
 

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