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Polarizing Light through Two Filters

  1. Jan 21, 2013 #1
    Hello, all.

    I have a general question related to something I read in a book right now. Not taking a course so I have no professor to ask, so I come to you all!

    To speed things up, I have this image I took from the book:
    xlvMtdrl.png

    My question is if the analyzer's polarizing axis was an arbitrary theta from the vertical, then E perpendicular would still lie on it's axis, right? As long as it wasn't perpendicular.

    I'm having a hard time visualizing this for some reason.
     
  2. jcsd
  3. Jan 22, 2013 #2
    E perpendicular is by definition taken perpendicularly to the analyzer's axis, no matter how the latter axis is oriented.
     
  4. Jan 22, 2013 #3

    rude man

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    Say the analyzer's axis is at angle θ where θ is measured clockwise from the vertical, same as with phi, the polarizer axis angle. Then the electric field vector at the analyzer output would be oriented as θ with magnitude cos(θ - phi). In your illustration, θ = 0.
     
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