Polarizing Light through Two Filters

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SUMMARY

The discussion focuses on the behavior of polarized light when passing through two filters, specifically analyzing the relationship between the electric field vector and the polarizing axes of the filters. The key conclusion is that the electric field component, E perpendicular, remains oriented perpendicularly to the analyzer's axis regardless of its angle θ, as long as θ is not perpendicular to the polarizer's axis. The magnitude of the electric field vector at the analyzer output is determined by the cosine of the angle difference between the analyzer and polarizer axes, expressed as cos(θ - φ).

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  • Basic concepts of optical filters and their alignment
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thiefjack
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Hello, all.

I have a general question related to something I read in a book right now. Not taking a course so I have no professor to ask, so I come to you all!

To speed things up, I have this image I took from the book:
xlvMtdrl.png


My question is if the analyzer's polarizing axis was an arbitrary theta from the vertical, then E perpendicular would still lie on it's axis, right? As long as it wasn't perpendicular.

I'm having a hard time visualizing this for some reason.
 
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E perpendicular is by definition taken perpendicularly to the analyzer's axis, no matter how the latter axis is oriented.
 
Say the analyzer's axis is at angle θ where θ is measured clockwise from the vertical, same as with phi, the polarizer axis angle. Then the electric field vector at the analyzer output would be oriented as θ with magnitude cos(θ - phi). In your illustration, θ = 0.
 

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