Pole of a function, as a geometric series

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 1K views
cragar
Messages
2,546
Reaction score
3

Homework Statement


Determine the order of the poles for the given function.
[itex]f(z)=\frac{1}{1+e^z}[/itex]

Homework Equations

The Attempt at a Solution


I know if you set the denominator equal to zero
you get z=ln(-1)
But if you expand the function as a geometric series ,
[itex]1-e^{z}+e^{2z}...[/itex]
I don't see how there is a pole in the geometric series expansion , there is no division by zero. [/B]
 
Physics news on Phys.org