- #1

Pietervv

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Member warned about not using the homework template

The question is:

Determine the Taylor series of f(x) at x=c(≠B) using geometric series

f(x)=A/(x-B)

My attempt to the solution is:

using geometric series :

f(x)= A/B

But i am not very sure if this is true.

Determine the Taylor series of f(x) at x=c(≠B) using geometric series

f(x)=A/(x-B)

^{4}My attempt to the solution is:

^{4}√f(x) =^{4}√A/((x-c)-B = (^{4}√A/B) * 1/(((x-c)/B)-1) = (^{4}√A/-B) * 1/(1-((x-c)/B))using geometric series :

^{4}√f(x) = (^{4}√A/-B) Σ((x-c)/B)^{n}f(x)= A/B

^{4}* Σ((x-c)/B)^{4n}with abs((x-c)/B)<1But i am not very sure if this is true.