Poles in the Lippmann-Schwinger Equation

  • Thread starter Thread starter tshafer
  • Start date Start date
  • Tags Tags
    Poles
Click For Summary
SUMMARY

The discussion centers on the poles in the Lippmann-Schwinger Equation, specifically within the context of deriving the Helmholtz Green function as presented in Sakurai's text. The integral in question features poles at q ≈ ±k ± iε', with a focus on the treatment of these poles during residue calculations. It is established that both the poles k + iε' and -k - iε' are considered, contributing to the e^{+ik|\vec{x}-\vec{x}'|} solution, while the poles -k + iε' and k - iε' yield the e^{-ik|\vec{x}-\vec{x}'|} solution. The choice of pole offset is contingent upon the boundary conditions applied.

PREREQUISITES
  • Understanding of the Lippmann-Schwinger Equation
  • Familiarity with complex analysis and residue theorem
  • Knowledge of the Helmholtz Green function
  • Basic principles of quantum mechanics as outlined in Sakurai's "Modern Quantum Mechanics"
NEXT STEPS
  • Study the residue theorem in complex analysis for deeper insights
  • Review the Helmholtz Green function derivation in Sakurai's "Modern Quantum Mechanics"
  • Explore boundary conditions in quantum mechanics and their implications on wave functions
  • Examine Arfken's "Mathematical Methods for Physicists" for advanced integration techniques
USEFUL FOR

Physicists, graduate students in quantum mechanics, and researchers focusing on scattering theory and complex analysis in physics.

tshafer
Messages
41
Reaction score
0
While deriving the Helmholtz Green function in Sakurai we come across the integral
\int_{-\infty}^{\infty}q\,dq\,\frac{e^{iq|\vec x-\vec x'|}-e^{-iq|\vec x-\vec x'|}}{q^2-k^2\mp i\varepsilon'}

This equation has poles at q \simeq \pm k\pm i\varepsilon', however when doing the residue calculation it seems that Sakurai only treats the poles k+i\varepsilon' and k-i\varepsilon', but not the companion poles poles -k-i\varepsilon' and -k+i\varepsilon'.

Is there a physical reason for this I am missing or do I have a mathematical error? If included, it seems the other poles would give both the \psi^{(\pm)} solutions over again?

Thanks!
Tom
 
Physics news on Phys.org
It looks like he's considering all four poles actually. When you offset the poles, to k+i\varepsilon' and -k-i\varepsilon', where \varepsilon'>0, one pole is included in contour for the e^{iq|\vec{x}-\vec{x}'|} integral, and the other pole is inside the contour for the e^{-iq|\vec{x}-\vec{x}'|} integral. Both integrals contribute to the e^{+ik|\vec{x}-\vec{x}'|} solution. The other two poles correspond to \varepsilon'<0 and yield the e^{-ik|\vec{x}-\vec{x}'|} solution. One is an incoming wave; the other is an outgoing wave. The choice of how you move the poles depends on your boundary conditions. Arfken (3rd edition), if you have it, discusses the integration on page 919.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
8
Views
7K
Replies
4
Views
5K
  • · Replies 2 ·
Replies
2
Views
8K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K