Polynomial relationship problem

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The discussion revolves around solving a polynomial relationship defined by q(x) = p(x)(x^5 - 2x + 2). For part (a), the task is to find the remainder of q(x) when divided by x - 2, using the fact that if x - 2 is a factor of p(x) - 5, then p(2) = 5. In part (b), p(x) is expressed as x^2 + ax + b, and since x - 1 is a factor of p(x) - 5, it leads to establishing an equation involving a and b. The solution suggests using the results from part (a) to create a second equation for simultaneous resolution of a and b. The overall focus is on applying polynomial root properties to solve for the unknowns.
Michael_Light
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Homework Statement



Polynomials p(x) and q(x) are given by relationship q(x)=p(x)(x5-2x+2).

a) If x-2 is a factor of p(x)-5 , find the remainder when q(x) is divided by x-2.

b) If p(x) is of the form x2+ax+b and x-1 is a factor of p(x)-5, find the values of a and b.


Homework Equations





The Attempt at a Solution



Can anyone help? :frown:
 
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For -

a) use the idea that if a polynomial p(x) has a root at a=0, then p(a)=0

b) Using the same idea as above, you should be able to establish an equation with the two unknowns a and b in it. To find another equation so that you can solve them simultaneously, use your answer from a).
 

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