Difficult polynomial question involving factor and remainder theorems

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Homework Help Overview

The discussion revolves around proving that \( (a-b) \) is a factor of \( a^5-b^5 \) and finding the other factor. The subject area includes polynomial factorization and the application of the remainder and factor theorems.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of polynomial division and the use of the factor and remainder theorems. There is uncertainty about the correct approach to proving the factorization and finding the other factor.

Discussion Status

Some participants are exploring polynomial division as a method to solve the problem, while others express confusion about the process and seek examples. There is acknowledgment of previous discussions related to similar problems, indicating a shared exploration of the topic.

Contextual Notes

Participants mention challenges with polynomial division and the need for clarification on the correct polynomial expressions to use in the context of the problem.

stfz
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Homework Statement



Prove that ##(a-b)## is a factor of ##a^5-b^5##, and find the other factor.

Homework Equations



Remainder theorem : remainder polynomial ##p(x)## divided by ##(x-a)## is equal to ##p(a)##
Factor theorem : if remainder = 0, then divisor was a factor of dividend.

The Attempt at a Solution



I think am able to prove that it is a factor:

##P(x) = x^5 - b^5##; we replace a with x
##P(x) = (x-b)Q(x) + 0## ; we assume that (x-b) is a factor
##P(b) = (b-b)Q(x) + 0 = 0 ##; proves that .. um.. I think I'm going the wrong way anyway. This doesn't really prove anything? er.. eh.. ?

And I can't really find the other factor
I could do most of the other questions in the exercise, but not this one (and other related ones!)

Any help would be appreciated
 
Last edited:
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stfz said:

Homework Statement



Prove that ##(a-b)## is a factor of ##a^5-b^5##, and find the other factor.

Homework Equations



Remainder theorem : remainder polynomial ##p(x)## divided by ##(x-a)## is equal to ##p(a)##
Factor theorem : if remainder = 0, then divisor was a factor of dividend.

The Attempt at a Solution



I think am able to prove that it is a factor:

##P(x) = x^5 - b^5##; we replace a with x
##P(x) = (x-b)Q(x) + 0## ; we assume that (x-b) is a factor
##P(b) = (b-b)Q(x) + 0 = 0 ##; proves that .. um.. I think I'm going the wrong way anyway. This doesn't really prove anything? er.. eh.. ?

And I can't really find the other factor
I could do most of the other questions in the exercise, but not this one (and other related ones!)

Any help would be appreciated
Do you know long division with polynomials, or synthetic division ?
 
Last edited:
Yes. However, attempting polynomial division on (x^5+b^5) didn't quite work for me. If that's how to solve the question, could someone give me an example?
 
stfz said:
Yes. However, attempting polynomial division on (x^5+b^5) didn't quite work for me. If that's how to solve the question, could someone give me an example?

Maybe that's because you want to divide (a^{5}-b^{5}) by (a - b).

Start off with a few warm-up exercises:

(a^{2}-b^{2})/(a-b)

(a^{3}-b^{3})/(a-b)

You should know the answer to the first exercise by inspection.
 
Woops, got what I missed. Thanks!
 

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