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Pool ball hits table, find an angle

  1. Nov 21, 2006 #1
    Figure 9-47 (attatched) shows a 0.165 kg cue ball as it bounces from the rail of a pool table. The ball's initial speed is 1.60 m/s, and the angle 1 = 30.0°. The bounce reverses the y component of the ball's velocity but does not alter the x component.

    (a) What is theta_2?
    (b) What is the change in the ball's linear momentum in unit-vector notation?

    I got the physics of part b, the trig of part a is messing me up. I went so far as to make a system:
    [tex]v\cos\theta_2=-v\cos\theta_1[/tex]
    [tex]v\sin\theta_2=v\sin\theta_1[/tex]

    As I thought! The angle must be in the second quadrant... so that means add 90 degrees, right? (And not 180-angle?)
    But I don't know how to go from the typical coordinate system used for measuring angles to the funky one shown in the diagram.
     

    Attached Files:

    Last edited: Nov 21, 2006
  2. jcsd
  3. Nov 21, 2006 #2
    Never mind. I got the correct answer of 30 degrees (I had started out by saying theta_2 = -30 degrees). But why? How is that allowed??? What kind of crazy notation are they using here (that apparantly is standard...)?
     
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