(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The acceleration of a particle is given by a(t)= - 2.1 m/s^{2}+ (3.1 m/s^{3})t

Find the initial velocity v_{0}such that the particle will have the same x-coordinate at time t=3.96 as it had at t=0.

What x-coordinate will the particle have at time t=3.96

2. Relevant equations

I'm assuming integration plays a factor in this, but I'm just not sure how to make the particle have the same position at t=3.96 and t=0

3. The attempt at a solution

Integral of 2.1+3.1t= 2.1t+3.1/2t^2+c

integrating again should give us:

1.05t^2+(3.1/6)t^3 +ct +k

I dont know where to go from there

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Position of a particle given an equation for acceleration

Tags:

**Physics Forums | Science Articles, Homework Help, Discussion**