(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

The acceleration of a particle is given by a(t)= - 2.1 m/s^{2}+ (3.1 m/s^{3})t

Find the initial velocity v_{0}such that the particle will have the same x-coordinate at time t=3.96 as it had at t=0.

What x-coordinate will the particle have at time t=3.96

2. Relevant equations

I'm assuming integration plays a factor in this, but I'm just not sure how to make the particle have the same position at t=3.96 and t=0

3. The attempt at a solution

Integral of 2.1+3.1t= 2.1t+3.1/2t^2+c

integrating again should give us:

1.05t^2+(3.1/6)t^3 +ct +k

I dont know where to go from there

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

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# Homework Help: Position of a particle given an equation for acceleration

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