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Position vector R of a particle moving x-y plane

  1. Jan 31, 2013 #1
    Hello, new to these forums! I'm working on my UPI homework, and I just want to verify if I'm doing something correctly. The problem:

    The position vector r of a particle moving in the x - y plane given by r = (2t^3)i + (6-7t^4)j, where r is in meters and t is in seconds.
    Calculate
    r
    v
    a
    when t = 2s

    Now, I'm pretty sure I know how to do it, but I don't get a second chance once I turn the homework in! :)

    So in the original equation, r is meters. So I'm thinking this is the displacement.
    If this is the displacement, I just plug in 2 for t and solve.
    Because that's the displacement, I can find a and v from the derivatives of the original function.

    Is this correct?
     
  2. jcsd
  3. Jan 31, 2013 #2

    tms

    User Avatar

    Sounds good. Just remember that [itex]\vec r[/itex] is a vector.
     
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