Potential Difference b/w Sphere & Cond. Shell | Electrostats

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SUMMARY

The discussion focuses on calculating the potential difference between a solid conducting sphere and a concentric conducting spherical shell in electrostatics. Initially, the sphere has a charge Q, and the shell is uncharged, resulting in a potential difference V. When the shell is charged with -3Q, the new potential difference must be determined using Gauss's Law and the integral of the electric field with respect to radius (V = ∫E dr).

PREREQUISITES
  • Understanding of electrostatics principles
  • Familiarity with Gauss's Law
  • Knowledge of electric potential and electric fields
  • Ability to perform integrals in the context of physics
NEXT STEPS
  • Study the application of Gauss's Law in electrostatics
  • Learn how to calculate electric potential differences in spherical systems
  • Explore the effects of charge distribution on potential in conductors
  • Review integral calculus as it applies to electric fields
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding electrostatic principles, particularly in the context of conductors and potential differences.

hellboydvd
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From Electrostatics:

A solid conducting sphere of charge Q is surrounded by an uncharged concentric conducting spherical shell. The potential difference between the sphere and the shell is V. If the shell is now given a charge of -3 Q , what is the new potential difference between them?
 
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you need to read the rules and post this in the HW section (this might get moved)

show what you have done and tell us where you are getting lost. you might want to begin with V=integral of E wrt r. use some gauss law stuff.
 

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