I need help with the attached exercise. Problem is not that I am not able to do it. You can find the field of an infinite cylinder with Gauss' law and then use that to find the potential difference.(adsbygoogle = window.adsbygoogle || []).push({});

My solutions notes however do it in a slightly different way, still arriving at the correct results. They use the expression for the potential of an infinite line:

V(r) = −1/(4[itex]\pi[/itex][itex]\epsilon[/itex]_{0})(2Q/L) ln(r/R_{0})

And simply use that to calculate the potential difference. Can someone explain to me why this would yield the same result?

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# Homework Help: Potential difference between two cylinders

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