Potential Energy and maximum velocity

[JSapit]

Homework Statement

The mass 0.40 kg is released and slides down the incline. The maximum velocity ( taken the instant before the mass reaches the bottom of the incline ) is 1.00 m/s. What is the kinetic energy at that time? What percentage of the potential energy of the system is not converted into kinetic energy due to friction? (converted into heat instead)

My question is with part b, and the percentage of potential energy lost due to friction.

Homework Equations

U=mgh
k=(1/2)mv^2

The Attempt at a Solution

The answer to question a, which is the amount of Kinetic Energy was 0.2 Joules.

However, I had no idea how to start part b.

Any help is appreciated, thanks!

 

[JSapit]

Bumperooski. I tried dividing the amount of PE by KE, and vice versa, but that didn't work. Still lost :/

 

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Is that all the info given?
Do they give any more info about the incline?

 

[funky]

the hypotenuse of the triangle is 40 cm with the vertical portion at 7 cm.

 

[<---]

I assume funky is working the same problem then?
Well, if you know the height, you can find the potential energy. And you know the final velocity, so you know the kinetic energy.
Now if all your potential energy didn't get converted to kinetic where did it go?
If you are having problems with just the percent part, the equation is KE/H * 100%